Skip to main content

EFFICIENCY OF A TRANSFORMER

Due to the losses in a transformer, its output power is less than the input power.
∴ Power output = Power input – Total losses
∴ Power input = Power output + Total losses = Power output + Pi + PCu
The ratio of power output to power input of any device is called its efficiency (η).
      images
Output power of a transformer at full-load = V2I2ftcosθ, where cosθ is the power factor of the load, I2ft is the secondary current at full load and V2 is the rated secondary voltage of the transformer.
Full-load copper loss of the transformer = I2ftR02.
∴     Efficiency of the transformer at full load is given by
images
Now V2I2ft = VA rating of the transformer.
∴    images
i.e.,    images
Efficiency of the transformer at any load m is given by
images
where m=images and PCuft is the Cu loss of the transformer at full load.

1.34 CONDITION FOR MAXIMUM EFFICIENCY

During working of a transformer at constant voltage and frequency, its efficiency varies with the load. Its efficiency increases as the load increases. At a certain load, its efficiency becomes maximum. If the transformer is further loaded, its efficiency starts decreasing. Figure 1.43 shows the plot of efficiency versus load current.
images
Figure 1.43 Comparison Efficiency and Current
To determine the condition of maximum efficiency, let us assume that the power factor of the load remains constant and the secondary terminal voltage (V2) is constant. Therefore, efficiency becomes only a function of load current (I2).
For maximum efficiency
images
Now,    images
∴    images
i.e.,  images
i.e.,    V2I2cosθ+Pi+I22R02V2I2cosθ–2I22R02=0
i.e.,    Pi=I22R02    (1.66)
To achieve maximum efficiency, Iron loss = Cu loss
i.e.,     Constant loss = Variable loss

1.34.1 Load Current at Maximum Efficiency

Let I2M be the load current at maximum efficiency.
∴    I2M2R02=Pi
i.e.,    images
Let I2ft be the full-load current.
∴    images
i.e.,    images
Equation (1.67) shows the load current in terms of full-load current at maximum efficiency.

1.34.2 kVA Supplied at Maximum Efficiency

For constant V2 the kVA supplied is the function of load current only.
∴    images
images
In general,
images
where    images

Comments

Popular posts from this blog

Transformer multiple choice questions part 1

Hello Engineer's Q.[1] A transformer transforms (a) frequency (b) voltage (c) current (d) voltage and current Ans : D Q.[2] Which of the following is not a basic element of a transformer ? (a) core (b) primary winding (c) secondary winding (d) mutual flux. Ans : D Q.[3] In an ideal transformer, (a) windings have no resistance (b) core has no losses (c) core has infinite permeability (d) all of the above. Ans : D Q.[4] The main purpose of using core in a transformer is to (a) decrease iron losses (b) prevent eddy current loss (c) eliminate magnetic hysteresis (d) decrease reluctance of the common magnetic circuit. Ans :D Q.[5] Transformer cores are laminated in order to (a) simplify its construction (b) minimize eddy current loss (c) reduce cost (d) reduce hysteresis loss. Ans : B Q.[6] A transformer having 1000 primary turns is connected to a 250-V a.c. supply. For a secondary voltage of 400 V, the number of secondary turns should be (a) 1600 (b) 250 (c) 400 (d) 1250 A...

Armature Voltage Control Method or Rheostatic Control of dc motor

Speed Control of D.C. Shunt Motor (Part2)  2. Armature Voltage Control Method or Rheostatic Control        The speed is directly proportional to the voltage applied across the armature. As the supply voltage is normally constant, the voltage across the armature can be controlled by adding a variable resistance in series with the armature as shown in the Fig. 1. Fig. 1 Rheostat control of shunt motor        The field winding is excited by the normal voltage hence I sh is rated and constant in this method. Initially the reheostat position is minimum and rated voltage gets applied across the armature. So speed is also rated. For a given load, armature current is fixed. So when extra resistance is added in the armature circuit, I a remains same and there is voltage drop across the resistance added ( I a R). Hence voltage across the armature decreases, decreasing the speed below normal value. By varyi...

Demagnetising and Cross Magnetizing Conductors

The conductors which are responsible for producing demagnetizing and distortion effects are shown in the Fig.1. Fig. 1        The brushes are lying along the new position of MNA which is at angle θ  from GNA. The conductors in the region AOC = BOD = 2θ  at the top and bottom of the armature are carrying current in such a direction as to send the flux in armature from right to left. Thus these conductors are in direct opposition to main field and called demagnetizing armature conductors.         The remaining armature conductors which are lying in the region AOD and BOC carry current in such a direction as to send the flux pointing vertically downwards i.e. at right angles to the main field flux. Hence these conductors are called cross magnetizing armature conductors which will cause distortion in main field flux.        These conductors are shown in the Fig. 2 Fig. 2  ...