Skip to main content

Load Characteristics of D.C. Shunt Generator

Consider the d.c. shunt generator shown in the Fig. 1. The internal characteristics is E Vs IL while the external characteristics is Vagainst IL.

Fig. 1 Internal characteristics
       Let us see the nature of these two characteristics.
       Ideally the induced e.m.f. is not dependent on the load current IL or armature current Ia. But as load current increases, the armature current Ia increases to supply load demand. As Ia increases, armature flux increases.
Note : The effect of flux produced by armature on the main flux produced by the field winding is called an armature reaction.
       Due to the armature reaction, main flux pattern gets distorted. Hence lesser flux gets linked with the armature conductors. This reduces the induced e.m.f.
Note : Thus the armature conductors. This reduces the induced e.m.f.
       This is shown in the Fig. 2.
Fig. 2  Internal characteristics
1.2 External Characteristics 
       For d.c. shunt generator we know that, E = Vt + Ia Ra neglecting other drops. So as load current increases IL, Ia increases. Thus the drop Ia Ra increases and terminal voltage V= E - Ia Ra decreases. But the value of armature resistance is very small, the drop in terminal voltage as IL changes from no load to full load is very small. This is shown in the Fig. 3. Hence d.c. shunt generator is called constant voltage generator.
Fig. 3  External characteristics
Why shunt generator load characteristics turns back when overloaded?
       Consider the external characteristics of d.c. shunt generator as shown in the Fig. 3(a). From to point P, the load resistance decreases hence load current increases and due to Ia Ra and armature reaction, the voltage decreases by small amount. Hence characteristics is drooping in nature.
       But if the load resistance is reduced beyond point P i.e. load IL is increased beyond P then it increases momentarilly. This is very large current and generator gets overloaded. Due to such a large current the armature reaction is severe and drop Ia Ra is also large due to which the voltage Vt drastically reduces. This causes the current to decreases from P to Q, rather than increasing. Thus on the curve pqr, the voltage goes on reducing rapidly and at point r becomes zero. Thus beyond point p, if the generator is loaded, the load characteristics turns back till the generator gets short circuited and the curve meets x axis at point r where voltage is zero. At this point, small E is present due to residual magnetism.
Note : In portion to p, the effect of decrease in load resistance dominates the effect of change in Vt as change in Vt is very small. While in portion 'pqr', the drastic reduction in Vt dominates the effect of decrease in load resistance hence curve turns back, reducing the load current.

Comments

Popular posts from this blog

Transformer multiple choice questions part 1

Hello Engineer's Q.[1] A transformer transforms (a) frequency (b) voltage (c) current (d) voltage and current Ans : D Q.[2] Which of the following is not a basic element of a transformer ? (a) core (b) primary winding (c) secondary winding (d) mutual flux. Ans : D Q.[3] In an ideal transformer, (a) windings have no resistance (b) core has no losses (c) core has infinite permeability (d) all of the above. Ans : D Q.[4] The main purpose of using core in a transformer is to (a) decrease iron losses (b) prevent eddy current loss (c) eliminate magnetic hysteresis (d) decrease reluctance of the common magnetic circuit. Ans :D Q.[5] Transformer cores are laminated in order to (a) simplify its construction (b) minimize eddy current loss (c) reduce cost (d) reduce hysteresis loss. Ans : B Q.[6] A transformer having 1000 primary turns is connected to a 250-V a.c. supply. For a secondary voltage of 400 V, the number of secondary turns should be (a) 1600 (b) 250 (c) 400 (d) 1250 A...

Condition for Maximum Power Developed In Synchronous Motor

The value of δ for which the mechanical power developed is maximum can be obtained as, Note : Thus when R a is negligible, θ = 90 o for maximum power developed. The corresponding torque is called pull out torque. 1.1 The Value of Maximum Power Developed        The value of maximum power developed can be obtained by substituting θ = δ in the equation of P m .        When R a is negligible,     θ = 90 o  and cos (θ) = 0 hence, . . .               R a = Z s cosθ   and X s = Z s sinθ        Substituting   cosθ = R a /Z s in equation (6b) we get,         Solving the above quadratic in E b we get,        As E b is completely dependent on excitation, the equation (8) gives the excitation limits for a...

Effect of Slip on Rotor Parameters : Part2

Effect of Slip on Rotor Parameters 2. Effect of Slip on Magnitude of Rotor Induced E.M.F        We have seen that when rotor is standstill, s  = 1, relative speed is maximum and maximum e.m.f. gets induced in the rotor. Let this e.m.f. be,                 E 2 = Rotor induced e.m.f. per phase on standstill condition         As rotor gains speed, the relative speed between rotor and rotating magnetic field decreases and hence induced e.m.f. in rotor also decreases as it is proportional to the relative speed N s - N. Let this e.m.f. be,                E 2r = Rotor induced e.m.f. per phase in running condition  Now        E 2r α N s while E 2r α N s - N        Di...